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Mathematics-Online course: Vector Calculus - Scalar Product

Law of Cosines

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In a triangle, for the angle $ \gamma$ opposite to side $ \overline{AB}$ the following holds true:

$\displaystyle c^2 = a^2 + b^2 - 2 ab \cos\gamma\, . $

\includegraphics[width=.4\linewidth]{a_cosinussatz}

If $ \gamma = \pi/2$ , then we obtain the special case of the Pythagorean Theorem: $ c^2=a^2+b^2$ .

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  automatically generated 10/30/2007