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Mathematics-Online problems:

Interactive Problem 304: Echelon Form (3x4)

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Transform the LSE

$\displaystyle \left(\begin{array}{cccc} 1 & 2 & 0 & 3 \\ 0 & 1 & 4 & 0 \\ 2 & 3... ...& 4 \end{array}\right) x = \left(\begin{array}{c} 1\\ 4\\ 2\end{array}\right) $

into Echelon-Form and determine the general solution $ x$.


Echelon-Form:

$ \left(\rule{0pt}{5.2ex}\right.$
1 2 0 3
0 1 4 0
$ -2$
$ \left.\rule{0pt}{5.2ex}\right)x=\left(\rule{0pt}{5.2ex}\right.$
1
4
$ \left.\rule{0pt}{5.2ex}\right)$


General solution:

$ x=\left(\rule{0pt}{7ex}\right.$
0
$ \left.\rule{0pt}{7ex}\right)+t\left(\rule{0pt}{7ex}\right.$
1
$ \left.\rule{0pt}{7ex}\right)$

   

(Authors: Höllig/Höfert)
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  automatically generated: 3/12/2018