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Mathematics-Online problems:

Interactive Problem 278: Jordan Form of a Matrix

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Find the Jordan canonical form $ J$ of the matrix

$\displaystyle A=\left(\begin{array}{rrrrrr} -2 & 0 & 1 & 0 & 0 & 0 \\ -1 & -1 ... ... & 0 \\ 0 & 0 & 0 & 0 & 1 & 0 \\ 3 & 0 & 2 & 1 & 0 & 1 \end{array}\right)\,. $


Solution: Give the diagonal $ d$ and the upper secondary diagonal $ n$ of $ J$. Sort the eigenvalues ascending and the Jordan blocks in descending size.

$ d=\big($ , , , , , $ \big)$
$ n=\big($ , , , , $ \big)$

   

(Authors: Blind/Höfert)
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  automatically generated: 8/11/2017